3x^2+13x-7408=0

Solution for 3x^2+13x-7408=0 equation:

3x^2+13x-7408=0

a = 3; b = 13; c = -7408;
Δ = b2-4ac
Δ = 132-4·3·(-7408)
Δ = 89065
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-\sqrt{89065}}{2*3}=\frac{-13-\sqrt{89065}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+\sqrt{89065}}{2*3}=\frac{-13+\sqrt{89065}}{6}
$